I just watched Eddie Woo's video on "What is 0 to the power of 0?" and got curious about the behavior of the function `def f(x): return x**x`. When I tested values like 0.000000000000000001, I noticed that it results in 1. Why does this happen? Is it due to overflow, rounding errors, or is there some special corner case in play?
5 Answers
Welcome to the fascinating realm of IEEE754 floating point arithmetic! It's a complex topic but super interesting how computers handle these calculations.
Totally, it’s all about precision limitations! I did some experiments with numpy and found that when you get to values like 10e-18, `x^x` can look like it's just 1 because of how floating point numbers work.
There are a few factors at play here. The implementation of float_pow in CPython has special cases for exponents like 0, and it usually defaults to 1 in scenarios like what you described. Depending on your environment and libraries, behavior can vary a lot when handling extreme floating point values.
The strange behavior you’re seeing is primarily due to floating point arithmetic precision. When you get down to numbers that small, the computer can struggle to represent them accurately, leading to unexpected results.
Exactly! In math, 0^0 is often labeled as indeterminate, but due to how computers handle floating-point math, it sometimes resolves to 1 to avoid complications. Checking out IEEE754 standards will give you some solid context on this.
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