I'm trying to design a function that takes an 8-bit integer and returns a corresponding 'bucket' based on the value's range. The idea is to check if the value lies within specific ranges, just like this example:
```c
int bucket_for_value(unsigned uint8_t x) {
if (x >= 0 && x = 32 && x = 64 && x = 96 && x = 128 && x = 160 && x = 192 && x = 224 && x < 256) return 7;
else return -1; // Out of range
}
```
The twist is that I want to control the likelihood of each range to be returned based on a single parameter, think of a knob that you can turn. When it's centered, there's an equal chance for each bucket. If turned all the way left, it should always return the first bucket (0), and if turned right, it should always return the last bucket (7). I also want positions between these extremes to weight the ranges accordingly. I'm looking for advice on how to implement this programming-wise. Thanks a bunch!
6 Answers
Could you clarify what the middle point of the knob represents? Like when it's a quarter of the way towards one extreme, how would that affect the ranges? Also, what's the ultimate reason behind wanting to shift from 0-256 to 0-7?
It seems like your math problem is already sorted out! You might want to rearrange the function to prioritize input validation at the start, eliminating unnecessary nesting in your checks. For example, do your out-of-range check first, then proceed with checking the ranges without needing 'else-if' after a return. This can make it cleaner and easier to follow.
I think I have a visualization for you! I created a graph that illustrates how you might desire the ranges to function based on the knob's position. You could consider using splines or some sort of curve that allows for smooth transitions between the weights. Check it out here: [Graph Example](https://ibb.co/1fnHxpdN). Let me know if this resonates with what you're looking for!
This looks spot on! Exactly what I was hoping for, thanks!
To implement this knob concept, I suggest defining its range first. Perhaps you can let the knob range from -7 to 7, where -7 would associate with the first bucket and +7 with the last. Divide 256 (your input range) by the effective number of ranges based on the knob value. This way, you'll create a weighted distribution across your buckets. It can get a bit complicated, but it should allow smooth adjustments as you turn the knob.
That makes sense! I like the idea of a negative and positive range to influence the buckets—thanks for the insight!
A straightforward approach would be to simplify your function using the division operation. You can divide the number by 32 and then use a switch-case statement for clarity. As for your knob idea, why not just set it to 0 on the left and 255 on the right? That way, the knob value directly maps to the ranges instead of complicating the expressions themselves.
A simple example would be using a knob value, 'p', that can be adjusted. At one end, the values would always return to the first bucket, and at another, the last. You'd essentially be shifting the input to always fall within a specific range depending on 'p'. It might look something like this, adjusted for what you want.
```c
int bucket_for_value(int x, int p) {
x = x - 30 + p;
// Add your conditions here...
}
```
This helps clarify things a lot! I appreciate you breaking it down for me.
Good questions! When the knob is at 25%, the chances should favor the lower numbers, so 'return 0' would have the highest probability. Essentially, I want to control the note lengths for a music sequencer. At one extreme, it should create short notes, while at the other, longer notes.