I'm running a simple Java code snippet that uses the Math.ceil function to round a floating point calculation. Here's what I have: `utils.LOG(Math.ceil(50.2f - 0.2f));`
In my mind, this should give me 51, since I know that 50.2 is actually stored as 50.200000762939453125 and 0.2 is stored as 0.20000000298023223876953125. Therefore, 50.2 - 0.2 should equal roughly 50.0000006971, and when I apply Math.ceil, I expect to get 51. Surprisingly, Java is outputting 50.0 instead.
I'm curious if Java has some optimizations in place regarding floating point precision loss. Can anyone explain why I'm not getting the expected result?
1 Answer
Floating point math is generally tricky in any programming language, and Java is no exception. When you perform arithmetic on float values, the results aren't always precise due to how these values are represented in binary. This is a common pitfall, so expecting a perfect output can often lead to confusion.
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