Understanding Memory References and Shallow Copies in JavaScript

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Asked By CuriousCoder42 On

I have a quick question regarding JavaScript objects. If I create an object like this: `const user = { profile: { age: 25 } };`, and then I make a shallow copy with `const clone = { ...user };`, what happens if I change `clone.profile.age` to 30? What will `console.log(user.profile.age);` output? I'm curious to hear your thoughts!

2 Answers

Answered By DevExplorer99 On

That's a great question! Practical understanding of this concept is key. You can create a shallow copy, but remember that nested objects still reference the original memory location. If you need to make sure that nested objects are also duplicated, you'd have to use a deep copy method instead.

Answered By CodeNinja88 On

The answer is 30! When you create a shallow copy, like with the spread operator, it only copies the top-level properties. Because `profile` is a nested object, both `user` and `clone` references point to the same memory location for the `profile` object. So modifying `clone.profile.age` actually changes `user.profile.age` too.

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