I encountered a question on a recent test that I got wrong, and I'm trying to wrap my head around it. Here's the code snippet from the test:
```c
int k = 0;
int i = 1;
while (i < N) {
k = k + sum(i);
i = i + 1;
}
```
I'm curious to know how many times the lines within the loop (c3, c4, and c5) execute based on the value of N. Any insights would be greatly appreciated!
3 Answers
It seems there’s some confusion around the variable N and its type. If N is defined as a numerical data type (like an int), that plays a crucial role here. If N is actually something like null, the loop will never execute. Just double-check to make sure you know what type N is supposed to be!
Actually, line c3 does run N times, but there's a bit of nuance on the loop behavior here. The way the loop is structured means it effectively checks the condition one extra time after the last iteration, so it’s correct to say that line 3 runs N times. Lines 4 and 5 will indeed run N-1 times since they won't execute when i equals N. But remember, the way you structure loops can really depend on whether you're counting checks or actual executions. It's easy to get those mixed up!
In your example, to clarify, line c3 (the while loop check) runs N times because it checks the condition once for every value from 1 up to N. Lines c4 and c5 will actually only execute N-1 times since the loop terminates when i reaches N, meaning it will not execute the lines on that final check where i is equal to N. So, for example, if N is 4, the lines would process for i = 1, 2, and 3 — giving you that N-1 execution count for lines 4 and 5.

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