I'm working on a password validation function in Python, and I need to ensure that the password has at least 5 numbers and 5 special characters to be considered valid. Right now, I'm using the `len()` function and the `re` module, but I feel like there's a better way to check these criteria in the string. Here's what I currently have: I'm taking the password input, searching for numbers and special characters, and checking the length. However, I'm stuck as the current method isn't quite cutting it. Any tips to improve this?
5 Answers
It looks like you're using `re.search()`, which only gets the first match. Instead, use `re.findall()` to find all matches of numbers. That way, you can count them and check if there are at least 5.
Here's a neat trick: you can build a set of the numbers in your password like this: `Numbers = {n for n in password if n.isdigit()}` and then just check the length of that set. It won't cover every special character by default, but you can easily tweak it to include whatever special characters you want!
Consider creating a function that loops through each character in the password, tallying how many numbers and special characters you encounter. Also, check that your max length condition works; you might want to change `>=` to `>` so it won't trigger an error when the length is exactly 25.
I think you're overthinking it! Just do a simple length check first, then loop through the password with a counter. For each character, check if it's a digit or special character and update your counters. Simple and clean!
You could create a simple loop to count the number of digits and special characters. Just check each character in the string and increment counters accordingly. Makes it easy to manage those checks without over-complicating things!
Could you show me a quick example of how to use `re.findall()` for this?