I've been working on a simple main menu project for my first year in IT, and I've run into some confusion regarding function parameters in C++. I'm trying to use an `average` function with the following prototype:
```cpp
void average(float prelim, float midterm, float finals);
```
Inside the function, I ask the user for input for these scores. I initially called the function like this:
```cpp
average(float prelim, midterm finals);
```
But that didn't work. I read that I should remove the parameters in the function call, so I tried:
```cpp
average();
```
That gave me an error about too few parameters. I then tried passing zeros for the parameters:
```cpp
average(0, 0, 0);
```
This resulted in an error about too many parameters. Eventually, I called it this way:
```cpp
average(0, 0);
```
And surprisingly, that worked! My question is, why did my last call work even though the function expects three parameters? Do I need to pass three arguments when calling the function?
4 Answers
Let me break this down for you: When you define a function with three parameters, you need to call it with three arguments like `average(0, 0, 0);`. If `average(0,0)` worked, then your function's definition must have changed. It’s also a common mistake to pass arguments to a function that doesn’t actually utilize them (like asking for input inside). It would be better to define your parameters inside the function if you’re taking user input.
Exactly! If you have `void average(float prelim, float midterm, float finals)`, you need to call it with three arguments. If `average(0, 0)` worked, it's probably because the function definition was modified at some point. Make sure you check your function's parameters. Passing parameters you aren't using in the function doesn't add much value.
The issue here is that your function definition declares three float parameters, but you're not using them as expected. If you want the function to take user input, you shouldn't require parameters at all. Here's a simpler approach: just define the function without parameters and declare the variables inside it to take user input. That will make things less confusing!
It seems like there's a misunderstanding here. The function is defined to take three float parameters, so `average(0, 0, 0);` should indeed work without any issues. If you're getting errors, perhaps there's a compile issue or you didn't save your changes? Also, why are you taking input inside the function when you're passing them as parameters? It might be better to get those values outside the function and then pass them in.
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