I'm working on a simple C++ program and I'm trying to understand why the output is 55. Here's the code I have:
```
#include
int main() {
char var1 = '3';
int var2 = 4;
std::cout << var1 + var2 << "n";
return 0;
}
```
3 Answers
Just to clarify, the output here shows the sum, not what the function returns. The program executes fine and prints out 55 as a result of the addition of the ASCII value of '3' and 4. Just remember, '3' is not the same as the integer 3!
You're right to think of ASCII! The decimal value of '3' is indeed 51. Therefore, when you add 4, it comes to 55, which is what gets printed.
The reason you're getting 55 as the output is that '3' is treated as a character, not as the number 3. In ASCII, the character '3' has a value of 51. So when you add that to var2 (which is 4), you actually perform 51 + 4, resulting in 55.
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