I have a C++ code snippet that's similar to this: `int exampleVar = 0;` and `while (exampleVar > 0) { exampleVar -= 1; }`. I'm trying to understand if the while loop will run at least once if the condition is already false before it starts. In this case, I'm curious about what the final value of `exampleVar` will be — will it be -1 or 0?
3 Answers
That's correct! A while loop checks the condition before it runs. If the condition is false at the start, like in your case, it won't execute the loop body even once. If you wanted it to run at least once regardless of the condition, you could look into using a do-while loop instead.
In your example, the condition `exampleVar > 0` is false from the get-go, so the `while` loop won't run at all. Since nothing happens inside the loop, `exampleVar` will remain 0. So, the final value of `exampleVar` is 0.
Right! Just to clarify, the do-while loop will run the code inside once before checking the condition, while the regular while loop checks it first. So, the value of `exampleVar` would stay at 0 for a while loop, but a do-while could set it to -1 after one execution.
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