How do I correctly handle variable expansion in my config file?

January 1, 2026 2 answers
Asked by CuriousCoder42
Hey folks! I've got a line in my config file that looks like this: `LOG_ROOT = ${HOME}/log`. In my script, I'm trying to read this entry and use it, but I'm running into issues with variable expansion when I write to the log file. Here's a snippet of my script: ```bash config_file="${1}"; mapfile -t config_entries < "${config_file}"; if (( ${#config_entries[*]} == 0 )); then (( error_count += 1 )); else for entry in "${config_entries[@]}"; do [[ -z "${entry}" ]] && continue; [[ "${entry}" =~ ^# ]] && continue; property_name="$(cut -d "=" -f 1 <<< "${entry}" | xargs)"; property_value="$(cut -d "=" -f 2- <<< "${entry}" | xargs)"; CONFIG_MAP["${property_name}"]="${property_value}"; done fi ``` When I try to write to the log file, set -x shows I'm getting the expected output, but the variable `${HOME}` isn't expanding as I expect. Instead, I just see `${HOME}/log/debug.log`. How can I fix this?

Answers

DevDude101
You don't need to end every line in your config file with a semicolon. Bash isn't particularly picky about that, and it might be causing some confusion. Just clean it up a little and you should be on the right track!
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ScriptGuru89
To make variable expansion work correctly in your setup, I'd suggest sourcing the config file directly. This allows bash to treat the assignments like regular variable assignments, which will help with expanding variables correctly. Also, ensure there are no spaces around the `=` in your config file; bash doesnโ€™t like that. Just remember, if you want this to behave as a property file for other applications, sourcing might not be the way to go.
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