What’s up with $null in the begin block causing issues in my PowerShell function?

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3
Asked By SillySocks42 On

I'm trying to automate account creation for new employees with a PowerShell script, and I ran into a problem that's driving me crazy. In the function I'm building, there's a $null variable in the begin{} block, and instead of just returning my desired PSCustomObject, it seems to be outputting as an array containing a null value along with the PSCustomObject. Here's a simplified version of my function:

```powershell
function New-EmployeeObject {
param (
[Parameter(Mandatory)]
[PSCustomObject]$Data
)
begin {
$EmployeeTemplate = [ordered]@{
'Employee_id' = 'id'
'Title' = 'title'
'Building' = 'building'
'PosType' = ''
'PosEndDate' = ''
}
$RandomVariable
#$RandomVariable = ''
}
process {
$EmployeeObj = New-Object -TypeName PSCustomObject -Property $EmployeeTemplate
$RandomVariable = "Headquarters"

return $EmployeeObj
}
}
$NewList = [System.Collections.Generic.List[object]]@()

foreach ($Line in $Csv) {
$NewGuy = New-EmployeeObject -Data $Line
$NewList.Add($NewGuy)
}
```

I noticed that when I don't initialize `$RandomVariable` as an empty string, my output for `$NewGuy` turns into an array: one element is $null while the other is the PSCustomObject I actually want. Any idea why this is happening? Is it due to treating $null like it's part of a collection, or something with how PowerShell manages scopes?

Edit: Thanks to u/godplaysdice_ for pointing out that in PowerShell, every statement contributes to output, unlike languages like C or C#.

3 Answers

Answered By CuriousCoder99 On

It sounds like your function is producing two outputs. The first output is the unset `$RandomVariable`, which is treated as null, and the second is your `$EmployeeObj`. That’s why you get an array instead of just the object you want. When you initialize `$RandomVariable` as an empty string, it doesn't output that null value, so you get only the PSCustomObject as expected.

Answered By PowerShellWizard88 On

I think the issue is that you're referencing `$RandomVariable` before it's been properly defined in your script. It just adds unnecessary output. If you want a clean return, make sure not to mention any variable that isn't explicitly assigned.

Answered By DebuggingDude23 On

You're on the right track! In PowerShell, calling an undefined variable like `$RandomVariable` causes it to output null. So in your `begin` block, that null ends up being part of the function output along with the `$EmployeeObj`. If you don't want any additional output, make sure to avoid referencing any undeclared variables.

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